What are the solutions to the equation r^2+10r-9=0 ?

The solutions to the equation r^2+10r-9=0 are r=-5+sqrt(34),r=-5-sqrt(34)

Find the zeros of r^2+10r-9=0

The zeros of r^2+10r-9=0 are r=-5+sqrt(34),r=-5-sqrt(34)

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r^{2} + 10 r - 9 = 0

r = - 5 + 34, r = - 5 - 34

Decimal Notation

r = 0.83095 \dots, r = - 10.83095 \dots

Solution steps

r^{2} + 10 r - 9 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot ( - 9 )}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot (- 9) = 234

r_{1, 2} = \frac{- 10 \pm 2 34}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- 10 + 2 34}{2 \cdot 1}, r_{2} = \frac{- 10 - 2 34}{2 \cdot 1}

r = \frac{- 10 + 2 34}{2 \cdot 1} : - 5 + 34

r = \frac{- 10 - 2 34}{2 \cdot 1} : - 5 - 34

The solutions to the quadratic equation are:

r = - 5 + 34, r = - 5 - 34

9 x^{2} - 12 = 0

(2 x - 7)^{2} + 16 = 0

10 x^{2} + 4 x + 3920 = 0

2 m^{2} + 4 = 0

x, 4 x^{2} + k x - 6 = 3

What are the solutions to the equation r^2+10r-9=0 ?
The solutions to the equation r^2+10r-9=0 are r=-5+sqrt(34),r=-5-sqrt(34)
Find the zeros of r^2+10r-9=0
The zeros of r^2+10r-9=0 are r=-5+sqrt(34),r=-5-sqrt(34)