What are the solutions to the equation 1/3 m^2+2m=4 ?

The solutions to the equation 1/3 m^2+2m=4 are m=-3+sqrt(21),m=-3-sqrt(21)

Find the zeros of 1/3 m^2+2m=4

The zeros of 1/3 m^2+2m=4 are m=-3+sqrt(21),m=-3-sqrt(21)

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\frac{1}{3} m^{2} + 2 m = 4

m = - 3 + 21, m = - 3 - 21

Decimal Notation

m = 1.58257 \dots, m = - 7.58257 \dots

Solution steps

\frac{1}{3} m^{2} + 2 m = 4

Multiply both sides by

3

m^{2} + 6 m = 12

Move

12

to the left side

m^{2} + 6 m - 12 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 12) = 221

m_{1, 2} = \frac{- 6 \pm 2 21}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 6 + 2 21}{2 \cdot 1}, m_{2} = \frac{- 6 - 2 21}{2 \cdot 1}

m = \frac{- 6 + 2 21}{2 \cdot 1} : - 3 + 21

m = \frac{- 6 - 2 21}{2 \cdot 1} : - 3 - 21

The solutions to the quadratic equation are:

m = - 3 + 21, m = - 3 - 21

4 m (3 m + 2) = m + 12

0 = 3 x^{2} + 12 x - 3

4 (h^{2}) - 64 = 0

2 x^{2} + 8 x = 15

2 (3 x + 5) = x^{2}

What are the solutions to the equation 1/3 m^2+2m=4 ?
The solutions to the equation 1/3 m^2+2m=4 are m=-3+sqrt(21),m=-3-sqrt(21)
Find the zeros of 1/3 m^2+2m=4
The zeros of 1/3 m^2+2m=4 are m=-3+sqrt(21),m=-3-sqrt(21)