What are the solutions to the equation -4x^2+16x+9=0 ?

The solutions to the equation -4x^2+16x+9=0 are x=-1/2 ,x= 9/2

Find the zeros of -4x^2+16x+9=0

The zeros of -4x^2+16x+9=0 are x=-1/2 ,x= 9/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 4 x^{2} + 16 x + 9 = 0

x = - \frac{1}{2}, x = \frac{9}{2}

Decimal Notation

x = - 0.5, x = 4.5

Solution steps

- 4 x^{2} + 16 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 ( - 4 ) \cdot 9}{2 ( - 4 )}

1 6^{2} - 4 (- 4) \cdot 9 = 20

x_{1, 2} = \frac{- 16 \pm 20}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 16 + 20}{2 ( - 4 )}, x_{2} = \frac{- 16 - 20}{2 ( - 4 )}

x = \frac{- 16 + 20}{2 ( - 4 )} : - \frac{1}{2}

x = \frac{- 16 - 20}{2 ( - 4 )} : \frac{9}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{2}, x = \frac{9}{2}

4 x^{2} - 65 x + 16 = 0

x (x + 3) = 70

z^{2} = (1 - i)^{\frac{1}{3}}

2 x (x + 7) = 0

5 - x^{2} = 4 x

What are the solutions to the equation -4x^2+16x+9=0 ?
The solutions to the equation -4x^2+16x+9=0 are x=-1/2 ,x= 9/2
Find the zeros of -4x^2+16x+9=0
The zeros of -4x^2+16x+9=0 are x=-1/2 ,x= 9/2