What are the solutions to the equation 15x^2+17x-4=0 ?

The solutions to the equation 15x^2+17x-4=0 are x= 1/5 ,x=-4/3

Find the zeros of 15x^2+17x-4=0

The zeros of 15x^2+17x-4=0 are x= 1/5 ,x=-4/3

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15 x^{2} + 17 x - 4 = 0

x = \frac{1}{5}, x = - \frac{4}{3}

Decimal Notation

x = 0.2, x = - 1.33333 \dots

Solution steps

15 x^{2} + 17 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 15 ( - 4 )}{2 \cdot 15}

1 7^{2} - 4 \cdot 15 (- 4) = 23

x_{1, 2} = \frac{- 17 \pm 23}{2 \cdot 15}

Separate the solutions

x_{1} = \frac{- 17 + 23}{2 \cdot 15}, x_{2} = \frac{- 17 - 23}{2 \cdot 15}

x = \frac{- 17 + 23}{2 \cdot 15} : \frac{1}{5}

x = \frac{- 17 - 23}{2 \cdot 15} : - \frac{4}{3}

The solutions to the quadratic equation are:

x = \frac{1}{5}, x = - \frac{4}{3}

2 x^{2} - 12 x + 1

x^{2} - 24 x - 6 = 0

13 - 13 x = (4 x + 3) (x - 1)

5 x^{2} + 10 x + 78 = 8

0.5 x^{2} + 0.875 x - 0.0525 = 0

What are the solutions to the equation 15x^2+17x-4=0 ?
The solutions to the equation 15x^2+17x-4=0 are x= 1/5 ,x=-4/3
Find the zeros of 15x^2+17x-4=0
The zeros of 15x^2+17x-4=0 are x= 1/5 ,x=-4/3