What are the solutions to the equation x^2-18-3x=0 ?

The solutions to the equation x^2-18-3x=0 are x=6,x=-3

Find the zeros of x^2-18-3x=0

The zeros of x^2-18-3x=0 are x=6,x=-3

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x^{2} - 18 - 3 x = 0

x = 6, x = - 3

Solution steps

x^{2} - 18 - 3 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 3 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 18 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 18) = 9

x_{1, 2} = \frac{- ( - 3 ) \pm 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 9}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 9}{2 \cdot 1}

x = \frac{- ( - 3 ) + 9}{2 \cdot 1} : 6

x = \frac{- ( - 3 ) - 9}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = 6, x = - 3

R^{2} + 7 R + 12 = 0

4 y^{2} - 9 y + 2 = 0

10 x = x^{2} - 11

216 t^{2} - 42.6 t + 80.84 = 9607

x^{2} + 6 x = 520

What are the solutions to the equation x^2-18-3x=0 ?
The solutions to the equation x^2-18-3x=0 are x=6,x=-3
Find the zeros of x^2-18-3x=0
The zeros of x^2-18-3x=0 are x=6,x=-3