What are the solutions to the equation -60=2(h+7)^2+4 ?

The solutions to the equation -60=2(h+7)^2+4 are h=4sqrt(2)i-7,h=-4sqrt(2)i-7

Find the zeros of -60=2(h+7)^2+4

The zeros of -60=2(h+7)^2+4 are h=4sqrt(2)i-7,h=-4sqrt(2)i-7

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- 60 = 2 (h + 7)^{2} + 4

h = 42 i - 7, h = - 42 i - 7

Solution steps

- 60 = 2 (h + 7)^{2} + 4

Switch sides

2 (h + 7)^{2} + 4 = - 60

Move

4

to the right side

2 (h + 7)^{2} = - 64

Divide both sides by

2

(h + 7)^{2} = - 32

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

h + 7 = - 32 : h = 42 i - 7

Solve

h + 7 = - - 32 : h = - 42 i - 7

The solutions to the quadratic equation are:

h = 42 i - 7, h = - 42 i - 7

2 x^{2} - 8 = 10

x^{2} + 6 x = 80

(x - 1)^{2} + (0 + 1)^{2} = 9

- 5 x^{2} + 20 x - 32

(x^{2} + 2 x - 3) = 6

What are the solutions to the equation -60=2(h+7)^2+4 ?
The solutions to the equation -60=2(h+7)^2+4 are h=4sqrt(2)i-7,h=-4sqrt(2)i-7
Find the zeros of -60=2(h+7)^2+4
The zeros of -60=2(h+7)^2+4 are h=4sqrt(2)i-7,h=-4sqrt(2)i-7