What are the solutions to the equation x^2=20x-51 ?

The solutions to the equation x^2=20x-51 are x=17,x=3

Find the zeros of x^2=20x-51

The zeros of x^2=20x-51 are x=17,x=3

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x^{2} = 20 x - 51

x = 17, x = 3

Solution steps

x^{2} = 20 x - 51

Move

51

to the left side

x^{2} + 51 = 20 x

Move

20 x

to the left side

x^{2} + 51 - 20 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 20 x + 51 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 1 \cdot 51}{2 \cdot 1}

(- 20)^{2} - 4 \cdot 1 \cdot 51 = 14

x_{1, 2} = \frac{- ( - 20 ) \pm 14}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 14}{2 \cdot 1}, x_{2} = \frac{- ( - 20 ) - 14}{2 \cdot 1}

x = \frac{- ( - 20 ) + 14}{2 \cdot 1} : 17

x = \frac{- ( - 20 ) - 14}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

x = 17, x = 3

x^{2} + 5 x + 2 = 0

x (x + 5)^{2} - x^{3} = 1

x^{2} - 7 x - 638 = 0

x, 6 x y^{2} = - 12 x^{2} y

8 x^{2} + 6 x = 4

What are the solutions to the equation x^2=20x-51 ?
The solutions to the equation x^2=20x-51 are x=17,x=3
Find the zeros of x^2=20x-51
The zeros of x^2=20x-51 are x=17,x=3