What are the solutions to the equation x^2+6x+4x+24=0 ?

The solutions to the equation x^2+6x+4x+24=0 are x=-4,x=-6

Find the zeros of x^2+6x+4x+24=0

The zeros of x^2+6x+4x+24=0 are x=-4,x=-6

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x^{2} + 6 x + 4 x + 24 = 0

x = - 4, x = - 6

Solution steps

x^{2} + 6 x + 4 x + 24 = 0

Refine

x^{2} + 10 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 24}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 24 = 2

x_{1, 2} = \frac{- 10 \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 2}{2 \cdot 1}, x_{2} = \frac{- 10 - 2}{2 \cdot 1}

x = \frac{- 10 + 2}{2 \cdot 1} : - 4

x = \frac{- 10 - 2}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

x = - 4, x = - 6

3 x^{2} = x + 3

v (v + 1) = 3 v^{2} + \frac{18}{4}

x, 36 x^{2} - 12 x + 1 = k^{2}

x^{2} - 11 + 24 = 0

y, x + (y - 7)^{2} = 0

What are the solutions to the equation x^2+6x+4x+24=0 ?
The solutions to the equation x^2+6x+4x+24=0 are x=-4,x=-6
Find the zeros of x^2+6x+4x+24=0
The zeros of x^2+6x+4x+24=0 are x=-4,x=-6