What are the solutions to the equation solvefor x,2f(x+2)^2=3(x+2) ?

The solutions to the equation solvefor x,2f(x+2)^2=3(x+2) are x=-2,x= 3/(2f)-2;\quad f\ne 0

Find the zeros of solvefor x,2f(x+2)^2=3(x+2)

The zeros of solvefor x,2f(x+2)^2=3(x+2) are x=-2,x= 3/(2f)-2;\quad f\ne 0

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solve for

x, 2 f (x + 2)^{2} = 3 (x + 2)

x = - 2, x = \frac{3}{2 f} - 2; f \neq = 0

Solution steps

2 f (x + 2)^{2} = 3 (x + 2)

Move

3 (x + 2)

to the left side

2 f (x + 2)^{2} - 3 (x + 2) = 0

Factor

2 f (x + 2)^{2} - 3 (x + 2) : (x + 2) (2 f (x + 2) - 3)

(x + 2) (2 f (x + 2) - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or 2 f (x + 2) - 3 = 0

Solve

x + 2 = 0 : x = - 2

Solve

2 f (x + 2) - 3 = 0 : x = \frac{3}{2 f} - 2; f \neq = 0

The solutions to the quadratic equation are:

x = - 2, x = \frac{3}{2 f} - 2; f \neq = 0

4 x^{2} - 15 = - 4 x

(11 x - 2)^{2} - 3 (11 x - 2) - 10 = 0

x^{2} - 6000 x - 3000000 = 0

5 x^{2} + 9 x = - 3

0 = x (x + 3)

What are the solutions to the equation solvefor x,2f(x+2)^2=3(x+2) ?
The solutions to the equation solvefor x,2f(x+2)^2=3(x+2) are x=-2,x= 3/(2f)-2;\quad f\ne 0
Find the zeros of solvefor x,2f(x+2)^2=3(x+2)
The zeros of solvefor x,2f(x+2)^2=3(x+2) are x=-2,x= 3/(2f)-2;\quad f\ne 0