What are the solutions to the equation 5x^2+9x=-3 ?

The solutions to the equation 5x^2+9x=-3 are x=(-9+sqrt(21))/(10),x=(-9-sqrt(21))/(10)

Find the zeros of 5x^2+9x=-3

The zeros of 5x^2+9x=-3 are x=(-9+sqrt(21))/(10),x=(-9-sqrt(21))/(10)

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5 x^{2} + 9 x = - 3

x = \frac{- 9 + 21}{10}, x = \frac{- 9 - 21}{10}

Decimal Notation

x = - 0.44174 \dots, x = - 1.35825 \dots

Solution steps

5 x^{2} + 9 x = - 3

Move

3

to the left side

5 x^{2} + 9 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 5 \cdot 3}{2 \cdot 5}

9^{2} - 4 \cdot 5 \cdot 3 = 21

x_{1, 2} = \frac{- 9 \pm 21}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 9 + 21}{2 \cdot 5}, x_{2} = \frac{- 9 - 21}{2 \cdot 5}

x = \frac{- 9 + 21}{2 \cdot 5} : \frac{- 9 + 21}{10}

x = \frac{- 9 - 21}{2 \cdot 5} : \frac{- 9 - 21}{10}

The solutions to the quadratic equation are:

x = \frac{- 9 + 21}{10}, x = \frac{- 9 - 21}{10}

0 = x (x + 3)

2 w^{2} + 3 w - 5 = 0

5 x^{2} + 6 x = 3

1.5 x^{2} - 13 x + 15 = 0

10 x^{2} + 7 x - 3 = 0

What are the solutions to the equation 5x^2+9x=-3 ?
The solutions to the equation 5x^2+9x=-3 are x=(-9+sqrt(21))/(10),x=(-9-sqrt(21))/(10)
Find the zeros of 5x^2+9x=-3
The zeros of 5x^2+9x=-3 are x=(-9+sqrt(21))/(10),x=(-9-sqrt(21))/(10)