What are the solutions to the equation m^2-6m+5=4m^2-8 ?

The solutions to the equation m^2-6m+5=4m^2-8 are m=-(3+4sqrt(3))/3 ,m=(4sqrt(3)-3)/3

Find the zeros of m^2-6m+5=4m^2-8

The zeros of m^2-6m+5=4m^2-8 are m=-(3+4sqrt(3))/3 ,m=(4sqrt(3)-3)/3

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m^{2} - 6 m + 5 = 4 m^{2} - 8

m = - \frac{3 + 4 3}{3}, m = \frac{4 3 - 3}{3}

Decimal Notation

m = - 3.30940 \dots, m = 1.30940 \dots

Solution steps

m^{2} - 6 m + 5 = 4 m^{2} - 8

Move

8

to the left side

m^{2} - 6 m + 13 = 4 m^{2}

Move

4 m^{2}

to the left side

- 3 m^{2} - 6 m + 13 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 ( - 3 ) \cdot 13}{2 ( - 3 )}

(- 6)^{2} - 4 (- 3) \cdot 13 = 83

m_{1, 2} = \frac{- ( - 6 ) \pm 8 3}{2 ( - 3 )}

Separate the solutions

m_{1} = \frac{- ( - 6 ) + 8 3}{2 ( - 3 )}, m_{2} = \frac{- ( - 6 ) - 8 3}{2 ( - 3 )}

m = \frac{- ( - 6 ) + 8 3}{2 ( - 3 )} : - \frac{3 + 4 3}{3}

m = \frac{- ( - 6 ) - 8 3}{2 ( - 3 )} : \frac{4 3 - 3}{3}

The solutions to the quadratic equation are:

m = - \frac{3 + 4 3}{3}, m = \frac{4 3 - 3}{3}

w^{2} + 8 w + 7 = 0

25 x^{2} - 35 x - 30 = 0

(3 x - 2) (7 x - 1) = 0

a^{2} - a = 1

\frac{1}{2} x^{2} - 4 x = 0

What are the solutions to the equation m^2-6m+5=4m^2-8 ?
The solutions to the equation m^2-6m+5=4m^2-8 are m=-(3+4sqrt(3))/3 ,m=(4sqrt(3)-3)/3
Find the zeros of m^2-6m+5=4m^2-8
The zeros of m^2-6m+5=4m^2-8 are m=-(3+4sqrt(3))/3 ,m=(4sqrt(3)-3)/3