What are the solutions to the equation A=x^2-6x-16 ?

The solutions to the equation A=x^2-6x-16 are x=3+sqrt(A+25),x=3-sqrt(A+25)

Find the zeros of A=x^2-6x-16

The zeros of A=x^2-6x-16 are x=3+sqrt(A+25),x=3-sqrt(A+25)

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A = x^{2} - 6 x - 16

x = 3 + A + 25, x = 3 - A + 25

Solution steps

A = x^{2} - 6 x - 16

Switch sides

x^{2} - 6 x - 16 = A

Move

A

to the left side

x^{2} - 6 x - 16 - A = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 16 - A )}{2 \cdot 1}

Simplify

(- 6)^{2} - 4 \cdot 1 \cdot (- 16 - A) : 2 A + 25

x_{1, 2} = \frac{- ( - 6 ) \pm 2 A + 25}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 A + 25}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 2 A + 25}{2 \cdot 1}

x = \frac{- ( - 6 ) + 2 A + 25}{2 \cdot 1} : 3 + A + 25

x = \frac{- ( - 6 ) - 2 A + 25}{2 \cdot 1} : 3 - A + 25

The solutions to the quadratic equation are:

x = 3 + A + 25, x = 3 - A + 25

x^{2} - 10 x + 9 = 0

4 x^{2} + 20 x + 23 = 0

x^{2} + 18 x + 42 = 0

3 x^{2} + 10 x + 9 = 0

1 - 5 x + x^{2} + 2 x = 1

What are the solutions to the equation A=x^2-6x-16 ?
The solutions to the equation A=x^2-6x-16 are x=3+sqrt(A+25),x=3-sqrt(A+25)
Find the zeros of A=x^2-6x-16
The zeros of A=x^2-6x-16 are x=3+sqrt(A+25),x=3-sqrt(A+25)