What are the solutions to the equation 2x^2-3x-32=0 ?

The solutions to the equation 2x^2-3x-32=0 are x=(3+sqrt(265))/4 ,x=(3-sqrt(265))/4

Find the zeros of 2x^2-3x-32=0

The zeros of 2x^2-3x-32=0 are x=(3+sqrt(265))/4 ,x=(3-sqrt(265))/4

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2 x^{2} - 3 x - 32 = 0

x = \frac{3 + 265}{4}, x = \frac{3 - 265}{4}

Decimal Notation

x = 4.81970 \dots, x = - 3.31970 \dots

Solution steps

2 x^{2} - 3 x - 32 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 2 ( - 32 )}{2 \cdot 2}

(- 3)^{2} - 4 \cdot 2 (- 32) = 265

x_{1, 2} = \frac{- ( - 3 ) \pm 265}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 265}{2 \cdot 2}, x_{2} = \frac{- ( - 3 ) - 265}{2 \cdot 2}

x = \frac{- ( - 3 ) + 265}{2 \cdot 2} : \frac{3 + 265}{4}

x = \frac{- ( - 3 ) - 265}{2 \cdot 2} : \frac{3 - 265}{4}

The solutions to the quadratic equation are:

x = \frac{3 + 265}{4}, x = \frac{3 - 265}{4}

3 x^{2} = 1 + 6 x

x^{2} + 8 x - 15

3 (x + 2)^{2} - 2 (x - 1) (x + 1) = 11 x + 18

2 x^{2} - 8 x - 5 = 0

x, 4 x^{2} - 21 x - 18 = 0

What are the solutions to the equation 2x^2-3x-32=0 ?
The solutions to the equation 2x^2-3x-32=0 are x=(3+sqrt(265))/4 ,x=(3-sqrt(265))/4
Find the zeros of 2x^2-3x-32=0
The zeros of 2x^2-3x-32=0 are x=(3+sqrt(265))/4 ,x=(3-sqrt(265))/4