What are the solutions to the equation 11x^2-13x=x(8-3x) ?

The solutions to the equation 11x^2-13x=x(8-3x) are x= 3/2 ,x=0

Find the zeros of 11x^2-13x=x(8-3x)

The zeros of 11x^2-13x=x(8-3x) are x= 3/2 ,x=0

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11 x^{2} - 13 x = x (8 - 3 x)

x = \frac{3}{2}, x = 0

Decimal Notation

x = 1.5, x = 0

Solution steps

11 x^{2} - 13 x = x (8 - 3 x)

Expand

x (8 - 3 x) : 8 x - 3 x^{2}

11 x^{2} - 13 x = 8 x - 3 x^{2}

Move

3 x^{2}

to the left side

14 x^{2} - 13 x = 8 x

Move

8 x

to the left side

14 x^{2} - 21 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 21 ) \pm ( - 21 ) ^{2} - 4 \cdot 14 \cdot 0}{2 \cdot 14}

(- 21)^{2} - 4 \cdot 14 \cdot 0 = 21

x_{1, 2} = \frac{- ( - 21 ) \pm 21}{2 \cdot 14}

Separate the solutions

x_{1} = \frac{- ( - 21 ) + 21}{2 \cdot 14}, x_{2} = \frac{- ( - 21 ) - 21}{2 \cdot 14}

x = \frac{- ( - 21 ) + 21}{2 \cdot 14} : \frac{3}{2}

x = \frac{- ( - 21 ) - 21}{2 \cdot 14} : 0

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = 0

(2 (x^{2}) - 40) 2 = 20

- 4 x^{2} - 8 x + 15 = 0

y, y^{2} = x + C x^{3}

(x - 8)^{2} = - 36

11 y^{2} - 12 y + 2 = 0

What are the solutions to the equation 11x^2-13x=x(8-3x) ?
The solutions to the equation 11x^2-13x=x(8-3x) are x= 3/2 ,x=0
Find the zeros of 11x^2-13x=x(8-3x)
The zeros of 11x^2-13x=x(8-3x) are x= 3/2 ,x=0