What are the solutions to the equation u^2=13u ?

The solutions to the equation u^2=13u are u=13,u=0

Find the zeros of u^2=13u

The zeros of u^2=13u are u=13,u=0

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u^{2} = 13 u

u = 13, u = 0

Solution steps

u^{2} = 13 u

Move

13 u

to the left side

u^{2} - 13 u = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 13)^{2} - 4 \cdot 1 \cdot 0 = 13

u_{1, 2} = \frac{- ( - 13 ) \pm 13}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- ( - 13 ) + 13}{2 \cdot 1}, u_{2} = \frac{- ( - 13 ) - 13}{2 \cdot 1}

u = \frac{- ( - 13 ) + 13}{2 \cdot 1} : 13

u = \frac{- ( - 13 ) - 13}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

u = 13, u = 0

x 3 = 3

(\frac{2 y ^{4}}{y ^{3}})^{- 2}

\frac{x}{2} - 5 = 3 x + 4

1 - \frac{1}{2}

1 + x^{2} + y^{2} + x^{2} y^{2}

What are the solutions to the equation u^2=13u ?
The solutions to the equation u^2=13u are u=13,u=0
Find the zeros of u^2=13u
The zeros of u^2=13u are u=13,u=0