What are the solutions to the equation solvefor y,9y^2=z(z-3)^2 ?

The solutions to the equation solvefor y,9y^2=z(z-3)^2 are y=(sqrt(z)(z-3))/3 ,y=-(sqrt(z)(z-3))/3

Find the zeros of solvefor y,9y^2=z(z-3)^2

The zeros of solvefor y,9y^2=z(z-3)^2 are y=(sqrt(z)(z-3))/3 ,y=-(sqrt(z)(z-3))/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solve for

y, 9 y^{2} = z (z - 3)^{2}

y = \frac{z ( z - 3 )}{3}, y = - \frac{z ( z - 3 )}{3}

Solution steps

9 y^{2} = z (z - 3)^{2}

Divide both sides by

9

y^{2} = \frac{z ( z - 3 ) ^{2}}{9}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = \frac{z ( z - 3 ) ^{2}}{9}, y = - \frac{z ( z - 3 ) ^{2}}{9}

Simplify

\frac{z ( z - 3 ) ^{2}}{9} : \frac{z ( z - 3 )}{3}

Simplify

- \frac{z ( z - 3 ) ^{2}}{9} : - \frac{z ( z - 3 )}{3}

y = \frac{z ( z - 3 )}{3}, y = - \frac{z ( z - 3 )}{3}

- 6 x^{2} + 7 x = - 10

x, I (x) = 5 x - x^{2}

x, 2 x^{2} - 3 x + 3 = 0

y, x^{2} + (y - 2)^{2} = 4

5 x^{2} - 50 x + 60 = - 5

What are the solutions to the equation solvefor y,9y^2=z(z-3)^2 ?
The solutions to the equation solvefor y,9y^2=z(z-3)^2 are y=(sqrt(z)(z-3))/3 ,y=-(sqrt(z)(z-3))/3
Find the zeros of solvefor y,9y^2=z(z-3)^2
The zeros of solvefor y,9y^2=z(z-3)^2 are y=(sqrt(z)(z-3))/3 ,y=-(sqrt(z)(z-3))/3