What are the solutions to the equation q^2+3q-19=-5 ?

The solutions to the equation q^2+3q-19=-5 are q=(-3+sqrt(65))/2 ,q=(-3-sqrt(65))/2

Find the zeros of q^2+3q-19=-5

The zeros of q^2+3q-19=-5 are q=(-3+sqrt(65))/2 ,q=(-3-sqrt(65))/2

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q^{2} + 3 q - 19 = - 5

q = \frac{- 3 + 65}{2}, q = \frac{- 3 - 65}{2}

Decimal Notation

q = 2.53112 \dots, q = - 5.53112 \dots

Solution steps

q^{2} + 3 q - 19 = - 5

Move

5

to the left side

q^{2} + 3 q - 14 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 14 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 14) = 65

q_{1, 2} = \frac{- 3 \pm 65}{2 \cdot 1}

Separate the solutions

q_{1} = \frac{- 3 + 65}{2 \cdot 1}, q_{2} = \frac{- 3 - 65}{2 \cdot 1}

q = \frac{- 3 + 65}{2 \cdot 1} : \frac{- 3 + 65}{2}

q = \frac{- 3 - 65}{2 \cdot 1} : \frac{- 3 - 65}{2}

The solutions to the quadratic equation are:

q = \frac{- 3 + 65}{2}, q = \frac{- 3 - 65}{2}

x, w = - 3 x^{2} + 5

q^{2} - 30 q + 200 = 0

x (x + 2) = 2 x + 25

x^{2} + 3 x = 8 x - 6

3 x^{2} - 5 = 11

What are the solutions to the equation q^2+3q-19=-5 ?
The solutions to the equation q^2+3q-19=-5 are q=(-3+sqrt(65))/2 ,q=(-3-sqrt(65))/2
Find the zeros of q^2+3q-19=-5
The zeros of q^2+3q-19=-5 are q=(-3+sqrt(65))/2 ,q=(-3-sqrt(65))/2