What are the solutions to the equation -3x^2-8x+9=0 ?

The solutions to the equation -3x^2-8x+9=0 are x=-(4+sqrt(43))/3 ,x=(sqrt(43)-4)/3

Find the zeros of -3x^2-8x+9=0

The zeros of -3x^2-8x+9=0 are x=-(4+sqrt(43))/3 ,x=(sqrt(43)-4)/3

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- 3 x^{2} - 8 x + 9 = 0

x = - \frac{4 + 43}{3}, x = \frac{43 - 4}{3}

Decimal Notation

x = - 3.51914 \dots, x = 0.85247 \dots

Solution steps

- 3 x^{2} - 8 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 ( - 3 ) \cdot 9}{2 ( - 3 )}

(- 8)^{2} - 4 (- 3) \cdot 9 = 243

x_{1, 2} = \frac{- ( - 8 ) \pm 2 43}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 43}{2 ( - 3 )}, x_{2} = \frac{- ( - 8 ) - 2 43}{2 ( - 3 )}

x = \frac{- ( - 8 ) + 2 43}{2 ( - 3 )} : - \frac{4 + 43}{3}

x = \frac{- ( - 8 ) - 2 43}{2 ( - 3 )} : \frac{43 - 4}{3}

The solutions to the quadratic equation are:

x = - \frac{4 + 43}{3}, x = \frac{43 - 4}{3}

b^{2} - 10 b + 10 = - 6

x^{2} + x - 72 = 0

x, x (100 - x - 2 y) = 0

7 x^{2} - 10 = 0

3 x (x - 2) = 11 x^{2} - 7 x

What are the solutions to the equation -3x^2-8x+9=0 ?
The solutions to the equation -3x^2-8x+9=0 are x=-(4+sqrt(43))/3 ,x=(sqrt(43)-4)/3
Find the zeros of -3x^2-8x+9=0
The zeros of -3x^2-8x+9=0 are x=-(4+sqrt(43))/3 ,x=(sqrt(43)-4)/3