What are the solutions to the equation (2x+3)(x-2)=4 ?

The solutions to the equation (2x+3)(x-2)=4 are x= 5/2 ,x=-2

Find the zeros of (2x+3)(x-2)=4

The zeros of (2x+3)(x-2)=4 are x= 5/2 ,x=-2

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(2 x + 3) (x - 2) = 4

x = \frac{5}{2}, x = - 2

Decimal Notation

x = 2.5, x = - 2

Solution steps

(2 x + 3) (x - 2) = 4

Expand

(2 x + 3) (x - 2) : 2 x^{2} - x - 6

2 x^{2} - x - 6 = 4

Move

4

to the left side

2 x^{2} - x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 ( - 10 )}{2 \cdot 2}

(- 1)^{2} - 4 \cdot 2 (- 10) = 9

x_{1, 2} = \frac{- ( - 1 ) \pm 9}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 9}{2 \cdot 2}, x_{2} = \frac{- ( - 1 ) - 9}{2 \cdot 2}

x = \frac{- ( - 1 ) + 9}{2 \cdot 2} : \frac{5}{2}

x = \frac{- ( - 1 ) - 9}{2 \cdot 2} : - 2

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = - 2

x, f = 3 x^{2} - 5 x - p

x^{2} + 62.1 x + 1 = 0

x^{2} - a x - 1 = 0

(7 x - 1)^{2} = 1

4 x^{2} - 24 x + 27

What are the solutions to the equation (2x+3)(x-2)=4 ?
The solutions to the equation (2x+3)(x-2)=4 are x= 5/2 ,x=-2
Find the zeros of (2x+3)(x-2)=4
The zeros of (2x+3)(x-2)=4 are x= 5/2 ,x=-2