What are the solutions to the equation 2(x-3)^2+1=101 ?

The solutions to the equation 2(x-3)^2+1=101 are x=5sqrt(2)+3,x=-5sqrt(2)+3

Find the zeros of 2(x-3)^2+1=101

The zeros of 2(x-3)^2+1=101 are x=5sqrt(2)+3,x=-5sqrt(2)+3

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2 (x - 3)^{2} + 1 = 101

x = 52 + 3, x = - 52 + 3

Decimal Notation

x = 10.07106 \dots, x = - 4.07106 \dots

Solution steps

2 (x - 3)^{2} + 1 = 101

Move

1

to the right side

2 (x - 3)^{2} = 100

Divide both sides by

2

(x - 3)^{2} = 50

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 3 = 50 : x = 52 + 3

Solve

x - 3 = - 50 : x = - 52 + 3

The solutions to the quadratic equation are:

x = 52 + 3, x = - 52 + 3

x^{2} - 7 = 93

2 x^{2} - 3 x - 8

(x - 2) x = 3 x (2 x + 1)

z^{2} + 6 z + 13 = 0

2 x^{2} + 8 x = 6

What are the solutions to the equation 2(x-3)^2+1=101 ?
The solutions to the equation 2(x-3)^2+1=101 are x=5sqrt(2)+3,x=-5sqrt(2)+3
Find the zeros of 2(x-3)^2+1=101
The zeros of 2(x-3)^2+1=101 are x=5sqrt(2)+3,x=-5sqrt(2)+3