What is factor 12x^2u+3x^2v+28yu+7yv ?

The solution to factor 12x^2u+3x^2v+28yu+7yv is (3x^2+7y)(4u+v)

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factor 12x^2u+3x^2v+28yu+7yv

factor

12 x^{2} u + 3 x^{2} v + 28 y u + 7 y v

(3 x^{2} + 7 y) (4 u + v)

Solution steps

12 x^{2} u + 3 x^{2} v + 28 y u + 7 y v

Rewrite as

= 3 \cdot 4 u x^{2} + 3 x^{2} v + 7 \cdot 4 u y + 7 y v

Factor out common term

4 u

= 4 u (3 x^{2} + 7 y) + 3 x^{2} v + 7 y v

Factor out common term

v

= 4 u (x^{2} \cdot 3 + 7 y) + v (3 x^{2} + 7 y)

Factor out common term

(x^{2} \cdot 3 + 7 y)

= (x^{2} \cdot 3 + 7 y) (4 u + v)

245 m^{2} n - 210 m n^{2} + 45 n^{3}

- x + 6 > - (2 x + 4)

- 2 (r - 13) + 10 > 6

f^{- 1} (6)

\frac{t}{4} \leq - 1

What is factor 12x^2u+3x^2v+28yu+7yv ?
The solution to factor 12x^2u+3x^2v+28yu+7yv is (3x^2+7y)(4u+v)