What are the solutions to the equation t(t)=-16t^2+4t+10 ?

The solutions to the equation t(t)=-16t^2+4t+10 are t=-(-2+sqrt(174))/(17),t=(2+sqrt(174))/(17)

Find the zeros of t(t)=-16t^2+4t+10

The zeros of t(t)=-16t^2+4t+10 are t=-(-2+sqrt(174))/(17),t=(2+sqrt(174))/(17)

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t (t) = - 16 t^{2} + 4 t + 10

t = - \frac{- 2 + 174}{17}, t = \frac{2 + 174}{17}

Decimal Notation

t = - 0.65828 \dots, t = 0.89358 \dots

Solution steps

t (t) = - 16 t^{2} + 4 t + 10

Expand

t (t) : t^{2}

t^{2} = - 16 t^{2} + 4 t + 10

Switch sides

- 16 t^{2} + 4 t + 10 = t^{2}

Move

t^{2}

to the left side

- 17 t^{2} + 4 t + 10 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 17 ) \cdot 10}{2 ( - 17 )}

4^{2} - 4 (- 17) \cdot 10 = 2174

t_{1, 2} = \frac{- 4 \pm 2 174}{2 ( - 17 )}

Separate the solutions

t_{1} = \frac{- 4 + 2 174}{2 ( - 17 )}, t_{2} = \frac{- 4 - 2 174}{2 ( - 17 )}

t = \frac{- 4 + 2 174}{2 ( - 17 )} : - \frac{- 2 + 174}{17}

t = \frac{- 4 - 2 174}{2 ( - 17 )} : \frac{2 + 174}{17}

The solutions to the quadratic equation are:

t = - \frac{- 2 + 174}{17}, t = \frac{2 + 174}{17}

x, x^{2} - x y + y - x + 1 = 0

p^{2} = 2 p + 15

v^{2} = 169

x^{2} - 3 x - 10

A (x) = 0.45 x^{2} - 41 x + 1059

What are the solutions to the equation t(t)=-16t^2+4t+10 ?
The solutions to the equation t(t)=-16t^2+4t+10 are t=-(-2+sqrt(174))/(17),t=(2+sqrt(174))/(17)
Find the zeros of t(t)=-16t^2+4t+10
The zeros of t(t)=-16t^2+4t+10 are t=-(-2+sqrt(174))/(17),t=(2+sqrt(174))/(17)