What are the solutions to the equation 3/2 (4x^2-20x+60)=0 ?

The solutions to the equation 3/2 (4x^2-20x+60)=0 are x= 5/2+i(sqrt(35))/2 ,x= 5/2-i(sqrt(35))/2

Find the zeros of 3/2 (4x^2-20x+60)=0

The zeros of 3/2 (4x^2-20x+60)=0 are x= 5/2+i(sqrt(35))/2 ,x= 5/2-i(sqrt(35))/2

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\frac{3}{2} (4 x^{2} - 20 x + 60) = 0

x = \frac{5}{2} + i \frac{35}{2}, x = \frac{5}{2} - i \frac{35}{2}

Solution steps

\frac{3}{2} (4 x^{2} - 20 x + 60) = 0

Multiply both sides by

2

3 (4 x^{2} - 20 x + 60) = 0

Expand

3 (4 x^{2} - 20 x + 60) : 12 x^{2} - 60 x + 180

12 x^{2} - 60 x + 180 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 60 ) \pm ( - 60 ) ^{2} - 4 \cdot 12 \cdot 180}{2 \cdot 12}

Simplify

(- 60)^{2} - 4 \cdot 12 \cdot 180 : 1235 i

x_{1, 2} = \frac{- ( - 60 ) \pm 12 35 i}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 60 ) + 12 35 i}{2 \cdot 12}, x_{2} = \frac{- ( - 60 ) - 12 35 i}{2 \cdot 12}

x = \frac{- ( - 60 ) + 12 35 i}{2 \cdot 12} : \frac{5}{2} + i \frac{35}{2}

x = \frac{- ( - 60 ) - 12 35 i}{2 \cdot 12} : \frac{5}{2} - i \frac{35}{2}

The solutions to the quadratic equation are:

x = \frac{5}{2} + i \frac{35}{2}, x = \frac{5}{2} - i \frac{35}{2}

x^{2} - 5 a + 8 x = 0

t, g (t - 1) = 5 - (t - 1)^{2}

x, f (x - 2) = x^{2} + 4 x + 7

2 x^{2} - 3 x + 1 = 38

y, x^{2} + y^{2} = C e^{2 x}

What are the solutions to the equation 3/2 (4x^2-20x+60)=0 ?
The solutions to the equation 3/2 (4x^2-20x+60)=0 are x= 5/2+i(sqrt(35))/2 ,x= 5/2-i(sqrt(35))/2
Find the zeros of 3/2 (4x^2-20x+60)=0
The zeros of 3/2 (4x^2-20x+60)=0 are x= 5/2+i(sqrt(35))/2 ,x= 5/2-i(sqrt(35))/2