What are the solutions to the equation t^2-5=3 ?

The solutions to the equation t^2-5=3 are t=2sqrt(2),t=-2sqrt(2)

Find the zeros of t^2-5=3

The zeros of t^2-5=3 are t=2sqrt(2),t=-2sqrt(2)

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t^{2} - 5 = 3

t = 22, t = - 22

Decimal Notation

t = 2.82842 \dots, t = - 2.82842 \dots

Solution steps

t^{2} - 5 = 3

Move

5

to the right side

t^{2} = 8

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = 8, t = - 8

8 = 22

- 8 = - 22

t = 22, t = - 22

0.15 x^{2} = 0.6

x^{2} + 8 x = 0

- y^{2} + 6 y - 12 = 0

x^{2} - c^{2} = c^{2} - x^{2}

(6 - n)^{2} = 36

What are the solutions to the equation t^2-5=3 ?
The solutions to the equation t^2-5=3 are t=2sqrt(2),t=-2sqrt(2)
Find the zeros of t^2-5=3
The zeros of t^2-5=3 are t=2sqrt(2),t=-2sqrt(2)