What are the solutions to the equation 0=x^2+25 ?

The solutions to the equation 0=x^2+25 are x=5i,x=-5i

Find the zeros of 0=x^2+25

The zeros of 0=x^2+25 are x=5i,x=-5i

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0 = x^{2} + 25

x = 5 i, x = - 5 i

Solution steps

0 = x^{2} + 25

Switch sides

x^{2} + 25 = 0

Move

25

to the right side

x^{2} = - 25

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 25, x = - - 25

- 25 = 5 i

- - 25 = - 5 i

x = 5 i, x = - 5 i

r^{2} - 12 r + 32 = 0

x, 0 = x^{2} + x - 12

x, y (x^{2} - 4) = 1 - x^{2}

6 x^{2} - 135 = 3 x^{2}

3 x^{2} + 36 x + 1

What are the solutions to the equation 0=x^2+25 ?
The solutions to the equation 0=x^2+25 are x=5i,x=-5i
Find the zeros of 0=x^2+25
The zeros of 0=x^2+25 are x=5i,x=-5i