What are the solutions to the equation 6=(3x+1)^2 ?

The solutions to the equation 6=(3x+1)^2 are x=(sqrt(6)-1)/3 ,x=(-sqrt(6)-1)/3

Find the zeros of 6=(3x+1)^2

The zeros of 6=(3x+1)^2 are x=(sqrt(6)-1)/3 ,x=(-sqrt(6)-1)/3

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6 = (3 x + 1)^{2}

x = \frac{6 - 1}{3}, x = \frac{- 6 - 1}{3}

Decimal Notation

x = 0.48316 \dots, x = - 1.14982 \dots

Solution steps

6 = (3 x + 1)^{2}

Switch sides

(3 x + 1)^{2} = 6

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x + 1 = 6 : x = \frac{6 - 1}{3}

Solve

3 x + 1 = - 6 : x = \frac{- 6 - 1}{3}

The solutions to the quadratic equation are:

x = \frac{6 - 1}{3}, x = \frac{- 6 - 1}{3}

12 x^{2} - 10 x + 5 = 0

(4 x - 1)^{2} - 123 x = (x + 5) (x - 8)

3 x^{2} + 10 x = 48

4.5 t^{2} - 27 t + 22.5 = 0

w^{2} = 7 (w - 4)

What are the solutions to the equation 6=(3x+1)^2 ?
The solutions to the equation 6=(3x+1)^2 are x=(sqrt(6)-1)/3 ,x=(-sqrt(6)-1)/3
Find the zeros of 6=(3x+1)^2
The zeros of 6=(3x+1)^2 are x=(sqrt(6)-1)/3 ,x=(-sqrt(6)-1)/3