What are the solutions to the equation x^2+4x=-21 ?

The solutions to the equation x^2+4x=-21 are x=-2+sqrt(17)i,x=-2-sqrt(17)i

Find the zeros of x^2+4x=-21

The zeros of x^2+4x=-21 are x=-2+sqrt(17)i,x=-2-sqrt(17)i

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x^{2} + 4 x = - 21

x = - 2 + 17 i, x = - 2 - 17 i

Solution steps

x^{2} + 4 x = - 21

Move

21

to the left side

x^{2} + 4 x + 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 21}{2 \cdot 1}

Simplify

4^{2} - 4 \cdot 1 \cdot 21 : 217 i

x_{1, 2} = \frac{- 4 \pm 2 17 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 2 17 i}{2 \cdot 1}, x_{2} = \frac{- 4 - 2 17 i}{2 \cdot 1}

x = \frac{- 4 + 2 17 i}{2 \cdot 1} : - 2 + 17 i

x = \frac{- 4 - 2 17 i}{2 \cdot 1} : - 2 - 17 i

The solutions to the quadratic equation are:

x = - 2 + 17 i, x = - 2 - 17 i

2 q^{2} + 7 q + 6 = 0

x^{2} - 17 = 32

- 2 - (5 x + 1) = 6 (- x + 1) 6 (- x + 1)

6 x^{2} + 19 x = 7

120 = 20 t + 5 t^{2}

What are the solutions to the equation x^2+4x=-21 ?
The solutions to the equation x^2+4x=-21 are x=-2+sqrt(17)i,x=-2-sqrt(17)i
Find the zeros of x^2+4x=-21
The zeros of x^2+4x=-21 are x=-2+sqrt(17)i,x=-2-sqrt(17)i