What are the solutions to the equation solvefor x,2x^2+5x=8 ?

The solutions to the equation solvefor x,2x^2+5x=8 are x=(-5+sqrt(89))/4 ,x=(-5-sqrt(89))/4

Find the zeros of solvefor x,2x^2+5x=8

The zeros of solvefor x,2x^2+5x=8 are x=(-5+sqrt(89))/4 ,x=(-5-sqrt(89))/4

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x, 2 x^{2} + 5 x = 8

x = \frac{- 5 + 89}{4}, x = \frac{- 5 - 89}{4}

Decimal Notation

x = 1.10849 \dots, x = - 3.60849 \dots

Solution steps

2 x^{2} + 5 x = 8

Move

8

to the left side

2 x^{2} + 5 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 2 ( - 8 )}{2 \cdot 2}

5^{2} - 4 \cdot 2 (- 8) = 89

x_{1, 2} = \frac{- 5 \pm 89}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 5 + 89}{2 \cdot 2}, x_{2} = \frac{- 5 - 89}{2 \cdot 2}

x = \frac{- 5 + 89}{2 \cdot 2} : \frac{- 5 + 89}{4}

x = \frac{- 5 - 89}{2 \cdot 2} : \frac{- 5 - 89}{4}

The solutions to the quadratic equation are:

x = \frac{- 5 + 89}{4}, x = \frac{- 5 - 89}{4}

y - 3 = y^{2} - 2 y - 13

(3 x + 4) (5 - \frac{x}{2}) = 0

x^{2} - 9 x = 8

9 x^{2} - 6 x - 3

(x - 4) (x + 2) = 5

What are the solutions to the equation solvefor x,2x^2+5x=8 ?
The solutions to the equation solvefor x,2x^2+5x=8 are x=(-5+sqrt(89))/4 ,x=(-5-sqrt(89))/4
Find the zeros of solvefor x,2x^2+5x=8
The zeros of solvefor x,2x^2+5x=8 are x=(-5+sqrt(89))/4 ,x=(-5-sqrt(89))/4