What are the solutions to the equation solvefor x,y=x^2-6x ?

The solutions to the equation solvefor x,y=x^2-6x are x=3+sqrt(y+9),x=3-sqrt(y+9)

Find the zeros of solvefor x,y=x^2-6x

The zeros of solvefor x,y=x^2-6x are x=3+sqrt(y+9),x=3-sqrt(y+9)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solve for

x, y = x^{2} - 6 x

x = 3 + y + 9, x = 3 - y + 9

Solution steps

y = x^{2} - 6 x

Switch sides

x^{2} - 6 x = y

Move

y

to the left side

x^{2} - 6 x - y = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - y )}{2 \cdot 1}

Simplify

(- 6)^{2} - 4 \cdot 1 \cdot (- y) : 2 9 + y

x_{1, 2} = \frac{- ( - 6 ) \pm 2 9 + y}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 9 + y}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 2 9 + y}{2 \cdot 1}

x = \frac{- ( - 6 ) + 2 9 + y}{2 \cdot 1} : 3 + y + 9

x = \frac{- ( - 6 ) - 2 9 + y}{2 \cdot 1} : 3 - y + 9

The solutions to the quadratic equation are:

x = 3 + y + 9, x = 3 - y + 9

x, f (x - 2) = x^{2} + 9 x + 5

- t^{2} + 12 t = 32

5 R^{2} - 10 R = 0

4 x - 4 x^{2} + 3 = 0

3 a - 4 = a (a - 3)

What are the solutions to the equation solvefor x,y=x^2-6x ?
The solutions to the equation solvefor x,y=x^2-6x are x=3+sqrt(y+9),x=3-sqrt(y+9)
Find the zeros of solvefor x,y=x^2-6x
The zeros of solvefor x,y=x^2-6x are x=3+sqrt(y+9),x=3-sqrt(y+9)