What are the solutions to the equation -4x^2-26x+190=6x-2 ?

The solutions to the equation -4x^2-26x+190=6x-2 are x=-12,x=4

Find the zeros of -4x^2-26x+190=6x-2

The zeros of -4x^2-26x+190=6x-2 are x=-12,x=4

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- 4 x^{2} - 26 x + 190 = 6 x - 2

x = - 12, x = 4

Solution steps

- 4 x^{2} - 26 x + 190 = 6 x - 2

Move

2

to the left side

- 4 x^{2} - 26 x + 192 = 6 x

Move

6 x

to the left side

- 4 x^{2} - 32 x + 192 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 32 ) \pm ( - 32 ) ^{2} - 4 ( - 4 ) \cdot 192}{2 ( - 4 )}

(- 32)^{2} - 4 (- 4) \cdot 192 = 64

x_{1, 2} = \frac{- ( - 32 ) \pm 64}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- ( - 32 ) + 64}{2 ( - 4 )}, x_{2} = \frac{- ( - 32 ) - 64}{2 ( - 4 )}

x = \frac{- ( - 32 ) + 64}{2 ( - 4 )} : - 12

x = \frac{- ( - 32 ) - 64}{2 ( - 4 )} : 4

The solutions to the quadratic equation are:

x = - 12, x = 4

x^{2} + 0.000002 x - 0.0000004 = 0

- 3 x^{2} + 8 x + 4 = 0

6 x^{2} + 7 x = 4

(x + 3) \cdot (x - 1) = 21

3 p^{2} - 2 p = 0

What are the solutions to the equation -4x^2-26x+190=6x-2 ?
The solutions to the equation -4x^2-26x+190=6x-2 are x=-12,x=4
Find the zeros of -4x^2-26x+190=6x-2
The zeros of -4x^2-26x+190=6x-2 are x=-12,x=4