What are the solutions to the equation (x+4)^2=-2 ?

The solutions to the equation (x+4)^2=-2 are x=sqrt(2)i-4,x=-sqrt(2)i-4

Find the zeros of (x+4)^2=-2

The zeros of (x+4)^2=-2 are x=sqrt(2)i-4,x=-sqrt(2)i-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x + 4)^{2} = - 2

x = 2 i - 4, x = - 2 i - 4

Solution steps

(x + 4)^{2} = - 2

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 4 = - 2 : x = 2 i - 4

Solve

x + 4 = - - 2 : x = - 2 i - 4

The solutions to the quadratic equation are:

x = 2 i - 4, x = - 2 i - 4

x^{2} + 4 x - 32 = 0

6 x (x - 1) = 5 - 19 x

(5 x + 6)^{2} = 2

x + 5 = (x + 3)^{2}

- x^{2} = 3 - 4 x

What are the solutions to the equation (x+4)^2=-2 ?
The solutions to the equation (x+4)^2=-2 are x=sqrt(2)i-4,x=-sqrt(2)i-4
Find the zeros of (x+4)^2=-2
The zeros of (x+4)^2=-2 are x=sqrt(2)i-4,x=-sqrt(2)i-4