What are the solutions to the equation m^2+16m=4 ?

The solutions to the equation m^2+16m=4 are m=2(sqrt(17)-4),m=-2(4+sqrt(17))

Find the zeros of m^2+16m=4

The zeros of m^2+16m=4 are m=2(sqrt(17)-4),m=-2(4+sqrt(17))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

m^{2} + 16 m = 4

m = 2 (17 - 4), m = - 2 (4 + 17)

Decimal Notation

m = 0.24621 \dots, m = - 16.24621 \dots

Solution steps

m^{2} + 16 m = 4

Move

4

to the left side

m^{2} + 16 m - 4 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

1 6^{2} - 4 \cdot 1 \cdot (- 4) = 417

m_{1, 2} = \frac{- 16 \pm 4 17}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 16 + 4 17}{2 \cdot 1}, m_{2} = \frac{- 16 - 4 17}{2 \cdot 1}

m = \frac{- 16 + 4 17}{2 \cdot 1} : 2 (17 - 4)

m = \frac{- 16 - 4 17}{2 \cdot 1} : - 2 (4 + 17)

The solutions to the quadratic equation are:

m = 2 (17 - 4), m = - 2 (4 + 17)

x^{2} + 19 x + 48 = 0

3 x^{3} + 8 = 9 x^{2} + 3 x^{3}

(x + 11)^{2} - 225 = 0

10 x^{2} + 2 x + 5 = 0

x, 4 x^{2} - 8 k x = 0

What are the solutions to the equation m^2+16m=4 ?
The solutions to the equation m^2+16m=4 are m=2(sqrt(17)-4),m=-2(4+sqrt(17))
Find the zeros of m^2+16m=4
The zeros of m^2+16m=4 are m=2(sqrt(17)-4),m=-2(4+sqrt(17))