What are the solutions to the equation 13^2=x^2+4^2 ?

The solutions to the equation 13^2=x^2+4^2 are x=3sqrt(17),x=-3sqrt(17)

Find the zeros of 13^2=x^2+4^2

The zeros of 13^2=x^2+4^2 are x=3sqrt(17),x=-3sqrt(17)

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1 3^{2} = x^{2} + 4^{2}

x = 317, x = - 317

Decimal Notation

x = 12.36931 \dots, x = - 12.36931 \dots

Solution steps

1 3^{2} = x^{2} + 4^{2}

Switch sides

x^{2} + 4^{2} = 1 3^{2}

Move

4^{2}

to the right side

x^{2} = 153

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 153, x = - 153

153 = 317

- 153 = - 317

x = 317, x = - 317

2 x (x - 4) = 3

5 x^{2} + 10 x - 895 = 0

11 x^{2} - 14 x - 16 = 0

(2 x - 3)^{2} + 4 = 5 (2 x + 9)

(X - 4)^{2} = 169

What are the solutions to the equation 13^2=x^2+4^2 ?
The solutions to the equation 13^2=x^2+4^2 are x=3sqrt(17),x=-3sqrt(17)
Find the zeros of 13^2=x^2+4^2
The zeros of 13^2=x^2+4^2 are x=3sqrt(17),x=-3sqrt(17)