What are the solutions to the equation 7x(x+4)+6=5 ?

The solutions to the equation 7x(x+4)+6=5 are x=(-14+3sqrt(21))/7 ,x=-(14+3sqrt(21))/7

Find the zeros of 7x(x+4)+6=5

The zeros of 7x(x+4)+6=5 are x=(-14+3sqrt(21))/7 ,x=-(14+3sqrt(21))/7

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7 x (x + 4) + 6 = 5

x = \frac{- 14 + 3 21}{7}, x = - \frac{14 + 3 21}{7}

Decimal Notation

x = - 0.03603 \dots, x = - 3.96396 \dots

Solution steps

7 x (x + 4) + 6 = 5

Expand

7 x (x + 4) + 6 : 7 x^{2} + 28 x + 6

7 x^{2} + 28 x + 6 = 5

Move

5

to the left side

7 x^{2} + 28 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 28 \pm 2 8 ^{2} - 4 \cdot 7 \cdot 1}{2 \cdot 7}

2 8^{2} - 4 \cdot 7 \cdot 1 = 621

x_{1, 2} = \frac{- 28 \pm 6 21}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- 28 + 6 21}{2 \cdot 7}, x_{2} = \frac{- 28 - 6 21}{2 \cdot 7}

x = \frac{- 28 + 6 21}{2 \cdot 7} : \frac{- 14 + 3 21}{7}

x = \frac{- 28 - 6 21}{2 \cdot 7} : - \frac{14 + 3 21}{7}

The solutions to the quadratic equation are:

x = \frac{- 14 + 3 21}{7}, x = - \frac{14 + 3 21}{7}

x (5 x - 8) = - 3

2 (x + 4)^{2} = 9

x^{2} - 5 (x + 6) = - 5 x

\frac{2}{5} x^{2} + 63 = 13

y^{2} = 18 - 7 y

What are the solutions to the equation 7x(x+4)+6=5 ?
The solutions to the equation 7x(x+4)+6=5 are x=(-14+3sqrt(21))/7 ,x=-(14+3sqrt(21))/7
Find the zeros of 7x(x+4)+6=5
The zeros of 7x(x+4)+6=5 are x=(-14+3sqrt(21))/7 ,x=-(14+3sqrt(21))/7