What are the solutions to the equation (x-4)^2-13=0 ?

The solutions to the equation (x-4)^2-13=0 are x=sqrt(13)+4,x=-sqrt(13)+4

Find the zeros of (x-4)^2-13=0

The zeros of (x-4)^2-13=0 are x=sqrt(13)+4,x=-sqrt(13)+4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x - 4)^{2} - 13 = 0

x = 13 + 4, x = - 13 + 4

Decimal Notation

x = 7.60555 \dots, x = 0.39444 \dots

Solution steps

(x - 4)^{2} - 13 = 0

Move

13

to the right side

(x - 4)^{2} = 13

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 4 = 13 : x = 13 + 4

Solve

x - 4 = - 13 : x = - 13 + 4

The solutions to the quadratic equation are:

x = 13 + 4, x = - 13 + 4

x, x^{2} y y^{1} = e^{y}

10 x^{2} - 30 = - 20 x

3 x^{2} + 2 x = 5

\frac{n ( n - 3 )}{2} = n

\frac{n ( n - 3 )}{2} = 9

What are the solutions to the equation (x-4)^2-13=0 ?
The solutions to the equation (x-4)^2-13=0 are x=sqrt(13)+4,x=-sqrt(13)+4
Find the zeros of (x-4)^2-13=0
The zeros of (x-4)^2-13=0 are x=sqrt(13)+4,x=-sqrt(13)+4