What are the solutions to the equation x^2+5+2=-4 ?

The solutions to the equation x^2+5+2=-4 are x=sqrt(11)i,x=-sqrt(11)i

Find the zeros of x^2+5+2=-4

The zeros of x^2+5+2=-4 are x=sqrt(11)i,x=-sqrt(11)i

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x^{2} + 5 + 2 = - 4

x = 11 i, x = - 11 i

Solution steps

x^{2} + 5 + 2 = - 4

Move

5

to the right side

x^{2} + 2 = - 9

Move

2

to the right side

x^{2} = - 11

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 11, x = - - 11

- 11 = 11 i

- - 11 = - 11 i

x = 11 i, x = - 11 i

(- x - 7)^{2} = 18

x^{2} - 8 x + 15 = (a x + b) (c x + d)

(2 x + 5)^{2} = 7

4 + 2 x - x^{2} = - \frac{1}{2} x

x^{2} - x - 20 = 0

What are the solutions to the equation x^2+5+2=-4 ?
The solutions to the equation x^2+5+2=-4 are x=sqrt(11)i,x=-sqrt(11)i
Find the zeros of x^2+5+2=-4
The zeros of x^2+5+2=-4 are x=sqrt(11)i,x=-sqrt(11)i