What are the solutions to the equation 2a^2+a=11a ?

The solutions to the equation 2a^2+a=11a are a=5,a=0

Find the zeros of 2a^2+a=11a

The zeros of 2a^2+a=11a are a=5,a=0

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2 a^{2} + a = 11 a

a = 5, a = 0

Solution steps

2 a^{2} + a = 11 a

Move

11 a

to the left side

2 a^{2} - 10 a = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

(- 10)^{2} - 4 \cdot 2 \cdot 0 = 10

a_{1, 2} = \frac{- ( - 10 ) \pm 10}{2 \cdot 2}

Separate the solutions

a_{1} = \frac{- ( - 10 ) + 10}{2 \cdot 2}, a_{2} = \frac{- ( - 10 ) - 10}{2 \cdot 2}

a = \frac{- ( - 10 ) + 10}{2 \cdot 2} : 5

a = \frac{- ( - 10 ) - 10}{2 \cdot 2} : 0

The solutions to the quadratic equation are:

a = 5, a = 0

x, x^{2} - 6 m x + m^{3} = 0

(3 - x)^{(2)} + x^{(2)} = 2 (5 - x)

4 x^{2} + 12 x - 17 = 0

0 = 3 x^{2} - 4 x - 1

0 = (x + 2)^{2} - 1

What are the solutions to the equation 2a^2+a=11a ?
The solutions to the equation 2a^2+a=11a are a=5,a=0
Find the zeros of 2a^2+a=11a
The zeros of 2a^2+a=11a are a=5,a=0