What are the solutions to the equation 33z+7z^2=10 ?

The solutions to the equation 33z+7z^2=10 are z= 2/7 ,z=-5

Find the zeros of 33z+7z^2=10

The zeros of 33z+7z^2=10 are z= 2/7 ,z=-5

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33 z + 7 z^{2} = 10

z = \frac{2}{7}, z = - 5

Decimal Notation

z = 0.28571 \dots, z = - 5

Solution steps

33 z + 7 z^{2} = 10

Move

10

to the left side

33 z + 7 z^{2} - 10 = 0

Write in the standard form

a x^{2} + b x + c = 0

7 z^{2} + 33 z - 10 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 33 \pm 3 3 ^{2} - 4 \cdot 7 ( - 10 )}{2 \cdot 7}

3 3^{2} - 4 \cdot 7 (- 10) = 37

z_{1, 2} = \frac{- 33 \pm 37}{2 \cdot 7}

Separate the solutions

z_{1} = \frac{- 33 + 37}{2 \cdot 7}, z_{2} = \frac{- 33 - 37}{2 \cdot 7}

z = \frac{- 33 + 37}{2 \cdot 7} : \frac{2}{7}

z = \frac{- 33 - 37}{2 \cdot 7} : - 5

The solutions to the quadratic equation are:

z = \frac{2}{7}, z = - 5

x^{2} + 52 x + 100 = 0

x^{2} + 9 = 3 x

7 x^{2} - 22 x + 16 = 0

2 (3 x^{2} - x) = 8 - 3 x

4 y^{2} = 72

What are the solutions to the equation 33z+7z^2=10 ?
The solutions to the equation 33z+7z^2=10 are z= 2/7 ,z=-5
Find the zeros of 33z+7z^2=10
The zeros of 33z+7z^2=10 are z= 2/7 ,z=-5