What are the solutions to the equation 9=-3x^2+5x ?

The solutions to the equation 9=-3x^2+5x are x= 5/6-i(sqrt(83))/6 ,x= 5/6+i(sqrt(83))/6

Find the zeros of 9=-3x^2+5x

The zeros of 9=-3x^2+5x are x= 5/6-i(sqrt(83))/6 ,x= 5/6+i(sqrt(83))/6

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9 = - 3 x^{2} + 5 x

x = \frac{5}{6} - i \frac{83}{6}, x = \frac{5}{6} + i \frac{83}{6}

Solution steps

9 = - 3 x^{2} + 5 x

Switch sides

- 3 x^{2} + 5 x = 9

Move

9

to the left side

- 3 x^{2} + 5 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 ( - 3 ) ( - 9 )}{2 ( - 3 )}

Simplify

5^{2} - 4 (- 3) (- 9) : 83 i

x_{1, 2} = \frac{- 5 \pm 83 i}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 5 + 83 i}{2 ( - 3 )}, x_{2} = \frac{- 5 - 83 i}{2 ( - 3 )}

x = \frac{- 5 + 83 i}{2 ( - 3 )} : \frac{5}{6} - i \frac{83}{6}

x = \frac{- 5 - 83 i}{2 ( - 3 )} : \frac{5}{6} + i \frac{83}{6}

The solutions to the quadratic equation are:

x = \frac{5}{6} - i \frac{83}{6}, x = \frac{5}{6} + i \frac{83}{6}

(x + 19)^{2} = - 9

3 t^{2} = 12 t - 15

x^{2} - 3 x - 2 = 0

x^{2} + 4 x + 11

- 2 x^{2} - 3 x - 5 = 0

What are the solutions to the equation 9=-3x^2+5x ?
The solutions to the equation 9=-3x^2+5x are x= 5/6-i(sqrt(83))/6 ,x= 5/6+i(sqrt(83))/6
Find the zeros of 9=-3x^2+5x
The zeros of 9=-3x^2+5x are x= 5/6-i(sqrt(83))/6 ,x= 5/6+i(sqrt(83))/6