What are the solutions to the equation 2x^2-13x=-6 ?

The solutions to the equation 2x^2-13x=-6 are x=6,x= 1/2

Find the zeros of 2x^2-13x=-6

The zeros of 2x^2-13x=-6 are x=6,x= 1/2

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2 x^{2} - 13 x = - 6

x = 6, x = \frac{1}{2}

Decimal Notation

x = 6, x = 0.5

Solution steps

2 x^{2} - 13 x = - 6

Move

6

to the left side

2 x^{2} - 13 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 2 \cdot 6}{2 \cdot 2}

(- 13)^{2} - 4 \cdot 2 \cdot 6 = 11

x_{1, 2} = \frac{- ( - 13 ) \pm 11}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 13 ) + 11}{2 \cdot 2}, x_{2} = \frac{- ( - 13 ) - 11}{2 \cdot 2}

x = \frac{- ( - 13 ) + 11}{2 \cdot 2} : 6

x = \frac{- ( - 13 ) - 11}{2 \cdot 2} : \frac{1}{2}

The solutions to the quadratic equation are:

x = 6, x = \frac{1}{2}

(x - 5)^{2} - 10 (x - 5) + 21 = 0

x, x^{2} + 2 x y - 2 x - 2 y - 6 = 0

x^{2} + 8 x = - 10 x - 76

3 (x + 6)^{2} = 54

x, p x^{2} + q x + r = (x + 2) (x + 2)

What are the solutions to the equation 2x^2-13x=-6 ?
The solutions to the equation 2x^2-13x=-6 are x=6,x= 1/2
Find the zeros of 2x^2-13x=-6
The zeros of 2x^2-13x=-6 are x=6,x= 1/2