What are the solutions to the equation 4=b^2 ?

The solutions to the equation 4=b^2 are b=2,b=-2

Find the zeros of 4=b^2

The zeros of 4=b^2 are b=2,b=-2

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4 = b^{2}

b = 2, b = - 2

Solution steps

4 = b^{2}

Switch sides

b^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 4, b = - 4

4 = 2

- 4 = - 2

b = 2, b = - 2

x^{2} + 24 x - 140 = 0

6 x^{2} - 23 x = - 7

(2 x - 3)^{2} = 4 x + 5

0 = 0.05 x - 0.0005 x^{2}

(2 x + 5)^{2} + 1 = 0

What are the solutions to the equation 4=b^2 ?
The solutions to the equation 4=b^2 are b=2,b=-2
Find the zeros of 4=b^2
The zeros of 4=b^2 are b=2,b=-2