What are the solutions to the equation -x^2+2x+63=0 ?

The solutions to the equation -x^2+2x+63=0 are x=-7,x=9

Find the zeros of -x^2+2x+63=0

The zeros of -x^2+2x+63=0 are x=-7,x=9

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- x^{2} + 2 x + 63 = 0

x = - 7, x = 9

Solution steps

- x^{2} + 2 x + 63 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 1 ) \cdot 63}{2 ( - 1 )}

2^{2} - 4 (- 1) \cdot 63 = 16

x_{1, 2} = \frac{- 2 \pm 16}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 2 + 16}{2 ( - 1 )}, x_{2} = \frac{- 2 - 16}{2 ( - 1 )}

x = \frac{- 2 + 16}{2 ( - 1 )} : - 7

x = \frac{- 2 - 16}{2 ( - 1 )} : 9

The solutions to the quadratic equation are:

x = - 7, x = 9

3 u^{2} - 5 u - 2 = 0

3 (y - 1)^{2} + 5 y = 3

(x - 5) (x + 1) = - 8

(2 y + 5)^{2} = 25

x^{2} + 12 x = 1

What are the solutions to the equation -x^2+2x+63=0 ?
The solutions to the equation -x^2+2x+63=0 are x=-7,x=9
Find the zeros of -x^2+2x+63=0
The zeros of -x^2+2x+63=0 are x=-7,x=9