What is 4x+3>15\lor-6x>= 12 ?

The solution to 4x+3>15\lor-6x>= 12 is x 3

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4x+3>15\lor-6x>= 12

4 x + 3 > 15 or - 6 x \geq 12

x \leq - 2 or x > 3

Interval Notation

(- \infty, - 2] \cup (3, \infty)

Solution steps

4 x + 3 > 15 or - 6 x \geq 12

4 x + 3 > 15 : x > 3

- 6 x \geq 12 : x \leq - 2

Combine the intervals

x > 3 or x \leq - 2

Merge Overlapping Intervals

x \leq - 2 or x > 3

\frac{2 x ^{- 2} y}{7 x ^{3} y ^{2}} \cdot \frac{14 x ^{5} y ^{3}}{x ^{0} y ^{5}}

x^{2} - 4 x - 1

7 x + 5 < - 9

9 x - 8 = - 2

\frac{3}{2} - 2 x \leq 4 x - (5 x + 6)

What is 4x+3>15\lor-6x>= 12 ?
The solution to 4x+3>15\lor-6x>= 12 is x<=-2\lor x>3