What are the solutions to the equation y^2-10y+22=0 ?

The solutions to the equation y^2-10y+22=0 are y=5+sqrt(3),y=5-sqrt(3)

Find the zeros of y^2-10y+22=0

The zeros of y^2-10y+22=0 are y=5+sqrt(3),y=5-sqrt(3)

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y^{2} - 10 y + 22 = 0

y = 5 + 3, y = 5 - 3

Decimal Notation

y = 6.73205 \dots, y = 3.26794 \dots

Solution steps

y^{2} - 10 y + 22 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 22}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 22 = 23

y_{1, 2} = \frac{- ( - 10 ) \pm 2 3}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 10 ) + 2 3}{2 \cdot 1}, y_{2} = \frac{- ( - 10 ) - 2 3}{2 \cdot 1}

y = \frac{- ( - 10 ) + 2 3}{2 \cdot 1} : 5 + 3

y = \frac{- ( - 10 ) - 2 3}{2 \cdot 1} : 5 - 3

The solutions to the quadratic equation are:

y = 5 + 3, y = 5 - 3

25 x^{2} + 16 x = 0

- z^{2} - 3 z - 13 = - 2 z^{2}

10 = x^{2} - 9 x

5 x^{2} - 90 x + 310 = 0

x^{2} + 12 x - 85 = 0

What are the solutions to the equation y^2-10y+22=0 ?
The solutions to the equation y^2-10y+22=0 are y=5+sqrt(3),y=5-sqrt(3)
Find the zeros of y^2-10y+22=0
The zeros of y^2-10y+22=0 are y=5+sqrt(3),y=5-sqrt(3)