What are the solutions to the equation -(x^2)/2+x=-1.5 ?

The solutions to the equation -(x^2)/2+x=-1.5 are x=-1,x=3

Find the zeros of -(x^2)/2+x=-1.5

The zeros of -(x^2)/2+x=-1.5 are x=-1,x=3

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- \frac{x ^{2}}{2} + x = - 1.5

x = - 1, x = 3

Solution steps

- \frac{x ^{2}}{2} + x = - 1.5

Multiply both sides by

10

- 5 x^{2} + 10 x = - 15

Move

15

to the left side

- 5 x^{2} + 10 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 ( - 5 ) \cdot 15}{2 ( - 5 )}

1 0^{2} - 4 (- 5) \cdot 15 = 20

x_{1, 2} = \frac{- 10 \pm 20}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 10 + 20}{2 ( - 5 )}, x_{2} = \frac{- 10 - 20}{2 ( - 5 )}

x = \frac{- 10 + 20}{2 ( - 5 )} : - 1

x = \frac{- 10 - 20}{2 ( - 5 )} : 3

The solutions to the quadratic equation are:

x = - 1, x = 3

y^{2} - 19 = 0

10 x^{2} - 7 x = - 2 x^{2} + 8 x

x^{2} + x = 2 x + 6

x, y = 3 x - x^{2}

2 x^{2} + 10 x = 14 + 2 x

What are the solutions to the equation -(x^2)/2+x=-1.5 ?
The solutions to the equation -(x^2)/2+x=-1.5 are x=-1,x=3
Find the zeros of -(x^2)/2+x=-1.5
The zeros of -(x^2)/2+x=-1.5 are x=-1,x=3