What are the solutions to the equation -6x^2-96x-480=0 ?

The solutions to the equation -6x^2-96x-480=0 are x=-8-4i,x=-8+4i

Find the zeros of -6x^2-96x-480=0

The zeros of -6x^2-96x-480=0 are x=-8-4i,x=-8+4i

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- 6 x^{2} - 96 x - 480 = 0

x = - 8 - 4 i, x = - 8 + 4 i

Solution steps

- 6 x^{2} - 96 x - 480 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 96 ) \pm ( - 96 ) ^{2} - 4 ( - 6 ) ( - 480 )}{2 ( - 6 )}

Simplify

(- 96)^{2} - 4 (- 6) (- 480) : 48 i

x_{1, 2} = \frac{- ( - 96 ) \pm 48 i}{2 ( - 6 )}

Separate the solutions

x_{1} = \frac{- ( - 96 ) + 48 i}{2 ( - 6 )}, x_{2} = \frac{- ( - 96 ) - 48 i}{2 ( - 6 )}

x = \frac{- ( - 96 ) + 48 i}{2 ( - 6 )} : - 8 - 4 i

x = \frac{- ( - 96 ) - 48 i}{2 ( - 6 )} : - 8 + 4 i

The solutions to the quadratic equation are:

x = - 8 - 4 i, x = - 8 + 4 i

(y + 6) (4 y - 5) = 0

x^{2} + 6 x - 8 = 0

8 x^{2} + 10 x - 25 = 0

2 x^{2} + x - 2 = x^{2}

x^{2} + 10 x = 13

What are the solutions to the equation -6x^2-96x-480=0 ?
The solutions to the equation -6x^2-96x-480=0 are x=-8-4i,x=-8+4i
Find the zeros of -6x^2-96x-480=0
The zeros of -6x^2-96x-480=0 are x=-8-4i,x=-8+4i