What are the solutions to the equation x(x+5)+3(x+5)=0 ?

The solutions to the equation x(x+5)+3(x+5)=0 are x=-3,x=-5

Find the zeros of x(x+5)+3(x+5)=0

The zeros of x(x+5)+3(x+5)=0 are x=-3,x=-5

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x (x + 5) + 3 (x + 5) = 0

x = - 3, x = - 5

Solution steps

x (x + 5) + 3 (x + 5) = 0

Expand

x (x + 5) + 3 (x + 5) : x^{2} + 8 x + 15

x^{2} + 8 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 15}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 15 = 2

x_{1, 2} = \frac{- 8 \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 2}{2 \cdot 1}, x_{2} = \frac{- 8 - 2}{2 \cdot 1}

x = \frac{- 8 + 2}{2 \cdot 1} : - 3

x = \frac{- 8 - 2}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = - 3, x = - 5

x, (x - 3)^{2} = - 4 p (y - 2)

2900 = x^{2} + 8 x

(x + 3)^{2} - 17 = 4 (x - 1) - x

4 x^{2} + 24 x + 35 = 0

2 (w + 1)^{2} = 72

What are the solutions to the equation x(x+5)+3(x+5)=0 ?
The solutions to the equation x(x+5)+3(x+5)=0 are x=-3,x=-5
Find the zeros of x(x+5)+3(x+5)=0
The zeros of x(x+5)+3(x+5)=0 are x=-3,x=-5