What are the solutions to the equation 3t^2-12=12t ?

The solutions to the equation 3t^2-12=12t are t=2(1+sqrt(2)),t=2(1-sqrt(2))

Find the zeros of 3t^2-12=12t

The zeros of 3t^2-12=12t are t=2(1+sqrt(2)),t=2(1-sqrt(2))

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3 t^{2} - 12 = 12 t

t = 2 (1 + 2), t = 2 (1 - 2)

Decimal Notation

t = 4.82842 \dots, t = - 0.82842 \dots

Solution steps

3 t^{2} - 12 = 12 t

Move

12 t

to the left side

3 t^{2} - 12 - 12 t = 0

Write in the standard form

a x^{2} + b x + c = 0

3 t^{2} - 12 t - 12 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 3 ( - 12 )}{2 \cdot 3}

(- 12)^{2} - 4 \cdot 3 (- 12) = 122

t_{1, 2} = \frac{- ( - 12 ) \pm 12 2}{2 \cdot 3}

Separate the solutions

t_{1} = \frac{- ( - 12 ) + 12 2}{2 \cdot 3}, t_{2} = \frac{- ( - 12 ) - 12 2}{2 \cdot 3}

t = \frac{- ( - 12 ) + 12 2}{2 \cdot 3} : 2 (1 + 2)

t = \frac{- ( - 12 ) - 12 2}{2 \cdot 3} : 2 (1 - 2)

The solutions to the quadratic equation are:

t = 2 (1 + 2), t = 2 (1 - 2)

6 x^{2} = 144

2 x^{2} = - 5 - 7 x

(3 x + 1)^{2} - (3 x - 1)^{2} = x^{2}

2 x^{2} + 3.7 x + 0.305 = 0

x^{2} - 54 = 3 x

What are the solutions to the equation 3t^2-12=12t ?
The solutions to the equation 3t^2-12=12t are t=2(1+sqrt(2)),t=2(1-sqrt(2))
Find the zeros of 3t^2-12=12t
The zeros of 3t^2-12=12t are t=2(1+sqrt(2)),t=2(1-sqrt(2))