What are the solutions to the equation 100=(x-1)(200-40x) ?

The solutions to the equation 100=(x-1)(200-40x) are x=(6-sqrt(6))/2 ,x=(6+sqrt(6))/2

Find the zeros of 100=(x-1)(200-40x)

The zeros of 100=(x-1)(200-40x) are x=(6-sqrt(6))/2 ,x=(6+sqrt(6))/2

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100 = (x - 1) (200 - 40 x)

x = \frac{6 - 6}{2}, x = \frac{6 + 6}{2}

Decimal Notation

x = 1.77525 \dots, x = 4.22474 \dots

Solution steps

100 = (x - 1) (200 - 40 x)

Expand

(x - 1) (200 - 40 x) : - 40 x^{2} + 240 x - 200

100 = - 40 x^{2} + 240 x - 200

Switch sides

- 40 x^{2} + 240 x - 200 = 100

Move

100

to the left side

- 40 x^{2} + 240 x - 300 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 240 \pm 24 0 ^{2} - 4 ( - 40 ) ( - 300 )}{2 ( - 40 )}

24 0^{2} - 4 (- 40) (- 300) = 406

x_{1, 2} = \frac{- 240 \pm 40 6}{2 ( - 40 )}

Separate the solutions

x_{1} = \frac{- 240 + 40 6}{2 ( - 40 )}, x_{2} = \frac{- 240 - 40 6}{2 ( - 40 )}

x = \frac{- 240 + 40 6}{2 ( - 40 )} : \frac{6 - 6}{2}

x = \frac{- 240 - 40 6}{2 ( - 40 )} : \frac{6 + 6}{2}

The solutions to the quadratic equation are:

x = \frac{6 - 6}{2}, x = \frac{6 + 6}{2}

\frac{4 a}{9} a = 5

x^{2} - 6 x - 2 = 0

3 x^{2} - x - 2 = 1

1 x^{2} - 2 x - 15 = 0

(x - 2)^{2} = (2 x + 3)^{2}

What are the solutions to the equation 100=(x-1)(200-40x) ?
The solutions to the equation 100=(x-1)(200-40x) are x=(6-sqrt(6))/2 ,x=(6+sqrt(6))/2
Find the zeros of 100=(x-1)(200-40x)
The zeros of 100=(x-1)(200-40x) are x=(6-sqrt(6))/2 ,x=(6+sqrt(6))/2