What are the solutions to the equation 4x^2+6x-18=0 ?

The solutions to the equation 4x^2+6x-18=0 are x= 3/2 ,x=-3

Find the zeros of 4x^2+6x-18=0

The zeros of 4x^2+6x-18=0 are x= 3/2 ,x=-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} + 6 x - 18 = 0

x = \frac{3}{2}, x = - 3

Decimal Notation

x = 1.5, x = - 3

Solution steps

4 x^{2} + 6 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 4 ( - 18 )}{2 \cdot 4}

6^{2} - 4 \cdot 4 (- 18) = 18

x_{1, 2} = \frac{- 6 \pm 18}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 6 + 18}{2 \cdot 4}, x_{2} = \frac{- 6 - 18}{2 \cdot 4}

x = \frac{- 6 + 18}{2 \cdot 4} : \frac{3}{2}

x = \frac{- 6 - 18}{2 \cdot 4} : - 3

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = - 3

(w + 6) (2 w + 6) = 216

56 (x + 1) + 56 x = - 15 x (x + 1)

x^{2} - 2

x^{2} - 10 x = - 40

x^{2} - 10 x = - 23

What are the solutions to the equation 4x^2+6x-18=0 ?
The solutions to the equation 4x^2+6x-18=0 are x= 3/2 ,x=-3
Find the zeros of 4x^2+6x-18=0
The zeros of 4x^2+6x-18=0 are x= 3/2 ,x=-3